Halogen acids react with alcohols to form alkyl halides. The reaction follows a nucleophilic substitution mechanism. What will be the major product of the following reaction?
`CH_3-overset(CH_3)overset(|)(CH)-underset(OH)undeset(|)(CH)-CH_3+HCl to`

Options

A. `CH_3underset(CH_3)underset(|)(CH)-underset(Cl)underset(|)(CH_3)`
B. `CH_3underset(Cl)underset(|)(CH)-underset(CH_3)underset(|)(CH)-CH_3`
C. `CH_3-underset(Cl)underset(|)overset(CH_3)overset(|)(C)-CH_2CH_3`
D. `CH_3CH_2CH_2CH_2CH_2Cl`

Explanation

To solve the problem, we need to analyze the reaction between the given alcohol and hydrochloric acid (HCl) to determine the major product formed through a nucleophilic substitution mechanism.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants are:
- An alcohol: \( CH_3-CH(CH_3)-CH(OH)-CH_3 \) (which can be simplified to \( CH_3-CH(CH_3)-C(OH)-CH_3 \))
- Hydrochloric acid (HCl)

2. **Understanding the Reaction**:
When an alcohol reacts with a halogen acid, the hydroxyl group (–OH) is replaced by a halogen atom (in this case, Cl from HCl). The reaction follows a nucleophilic substitution mechanism.

3. **Formation of Carbocation**:
The hydroxyl group (–OH) can be protonated by HCl, making it a better leaving group (water, H2O). The oxygen atom in the alcohol has lone pairs, allowing it to act as a nucleophile. When the –OH group leaves, a carbocation is formed.

4. **Identify the Type of Carbocation**:
The structure of the alcohol indicates that upon the departure of the –OH group, a secondary carbocation is formed:
- The structure after the departure of –OH is \( CH_3-CH(CH_3)-C^+(CH_3) \) (where \( C^+ \) indicates the positively charged carbon).

5. **Rearrangement of Carbocation**:
Since secondary carbocations can rearrange to form more stable carbocations, we check for possible rearrangements. A hydride shift can occur from one of the adjacent carbon atoms to the carbocation, leading to the formation of a tertiary carbocation:
- The hydride from the adjacent carbon can shift to the carbocation, forming a tertiary carbocation.

6. **Final Product Formation**:
The nucleophile (Cl-) will then attack the more stable tertiary carbocation, resulting in the formation of the major product:
- The final product will be \( CH_3-CH(CH_3)-C(Cl)(CH_3) \).

7. **Conclusion**:
The major product of the reaction is a tertiary alkyl halide, specifically \( CH_3-CH(CH_3)-C(Cl)(CH_3) \).

### Major Product:
The major product formed from the reaction is:
\[ CH_3-CH(CH_3)-C(Cl)(CH_3) \]