An alkene `CH_(3)CH = CH_(2)` is treated with `B_(2)H_(6)` in presence of `H_(2)O_(2)` . The final product formed is

Options

A. `CH_(3)CH_(2)CHO`
B. `CH_(3)CH(OH)CH_(3)`
C. `CH_(3)CH_(2)CH_(2) OH`
D. `(CH_(3)CH_(2)CH_(2))_(3)B`

Explanation

To solve the problem, we need to determine the final product formed when the alkene CH₃CH=CH₂ is treated with B₂H₆ in the presence of H₂O₂. This reaction involves hydroboration-oxidation, which follows specific steps. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Alkene
The given alkene is CH₃CH=CH₂. This is a three-carbon alkene known as propene (or prop-1-ene).

**Hint:** Recognize the structure of the alkene and its name based on the number of carbons and the position of the double bond.

### Step 2: Understand the Reaction Conditions
The alkene is treated with B₂H₆ (diborane) in the presence of H₂O₂ (hydrogen peroxide). This indicates that we are performing a hydroboration-oxidation reaction.

**Hint:** Remember that hydroboration-oxidation involves two main steps: hydroboration (addition of boron) followed by oxidation (conversion to alcohol).

### Step 3: Hydroboration Step
In the hydroboration step, B₂H₆ adds across the double bond of the alkene. According to the anti-Markovnikov rule, the boron atom will attach to the less substituted carbon (the one with more hydrogen atoms).

- In CH₃CH=CH₂, the first carbon (C1) has 2 hydrogen atoms, and the second carbon (C2) has 1 hydrogen atom. Thus, boron will attach to C1.

**Hint:** Apply the anti-Markovnikov rule to determine where the boron will add.

### Step 4: Formation of Trialkylborane
After the hydroboration step, we form a trialkylborane intermediate. The structure after hydroboration will be:
- C1: CH₃-CH₂ (with boron attached)
- C2: CH₂-B (where B is the boron atom)

This results in the structure: CH₃-CH₂-CH₂-B.

**Hint:** Visualize the structure of the trialkylborane to understand the positioning of the boron atom.

### Step 5: Oxidation Step
In the oxidation step, the trialkylborane is treated with H₂O₂ in the presence of a base (usually NaOH). This converts the boron to an alcohol group (OH) and replaces the boron atom.

- The boron atom will be replaced by an OH group at the same carbon where it was attached (C1).

**Hint:** Remember that the oxidation step converts the boron to an alcohol group.

### Step 6: Final Product
After the oxidation, the final product will be:
- CH₃-CH₂-CH₂-OH, which is propan-1-ol.

**Hint:** Identify the final structure and name the compound based on the number of carbons and the functional group.

### Conclusion
The final product formed from the reaction of CH₃CH=CH₂ with B₂H₆ in the presence of H₂O₂ is propan-1-ol (CH₃CH₂CH₂OH).

### Summary of Final Product:
The final product is **CH₃CH₂CH₂OH** (propan-1-ol).