Ansisole on reaction ith chloromethane in presence of anhydrous `AlCl_3` gives

Options

A. a-methyl anisole and p-methoxy anisole
B. p-methyl anisole and p -methoxy anisole
C. a-methyl anisole and p-methyl anisole
D. a-methoxy acetophenone and p-methoxy acetophenone

Explanation

To solve the question, we need to analyze the reaction of anisole (OCH3) with chloromethane (CH3Cl) in the presence of anhydrous aluminum chloride (AlCl3). This reaction is a Friedel-Crafts alkylation.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are anisole (C6H5OCH3) and chloromethane (CH3Cl), with anhydrous aluminum chloride (AlCl3) as a catalyst.

2. **Understand the Mechanism**:
- In Friedel-Crafts alkylation, AlCl3 acts as a Lewis acid and helps generate a more reactive electrophile from chloromethane.
- The reaction of CH3Cl with AlCl3 produces a methyl cation (CH3+) and AlCl4-.

3. **Resonance Structures of Anisole**:
- Anisole has a methoxy group (-OCH3) which is an electron-donating group. This group stabilizes the positive charge through resonance.
- The resonance structures show that the methoxy group directs electrophilic substitution to the ortho and para positions of the aromatic ring.

4. **Electrophilic Attack**:
- The methyl cation (CH3+) can attack the ortho or para positions of the anisole ring due to the electron-donating effect of the methoxy group.
- This leads to the formation of two possible products:
- Ortho-methyl anisole (1,2-dimethoxybenzene)
- Para-methyl anisole (1,4-dimethoxybenzene)

5. **Formation of Byproducts**:
- After the electrophilic attack, the reaction will also produce AlCl3 and HCl as byproducts.

6. **Final Products**:
- The final products of the reaction are ortho-methyl anisole and para-methyl anisole.

### Conclusion:
The correct answer to the question is that anisole reacts with chloromethane in the presence of anhydrous AlCl3 to give ortho-methyl anisole and para-methyl anisole.