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0.48 g of a sample of a compound contain...

0.48 g of a sample of a compound containing boron and oxygen contains 0.192 g of boron and 0.288 g of oxygen. What will be the percentage composition of the compound?

A

60% and 40% B and O respectively

B

40% and 60% B and O respectively

C

30% and 70% B and O respectively

D

70% and 30% B and O respectively

Text Solution

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The correct Answer is:
To find the percentage composition of the compound containing boron and oxygen, we will follow these steps: ### Step 1: Identify the given data - Total mass of the compound = 0.48 g - Mass of boron = 0.192 g - Mass of oxygen = 0.288 g ### Step 2: Calculate the percentage composition of boron To calculate the percentage composition of boron, we use the formula: \[ \text{Percentage of Boron} = \left( \frac{\text{Mass of Boron}}{\text{Total Mass}} \right) \times 100 \] Substituting the values: \[ \text{Percentage of Boron} = \left( \frac{0.192 \, \text{g}}{0.48 \, \text{g}} \right) \times 100 \] Calculating this gives: \[ \text{Percentage of Boron} = \left( 0.4 \right) \times 100 = 40\% \] ### Step 3: Calculate the percentage composition of oxygen To calculate the percentage composition of oxygen, we use the same formula: \[ \text{Percentage of Oxygen} = \left( \frac{\text{Mass of Oxygen}}{\text{Total Mass}} \right) \times 100 \] Substituting the values: \[ \text{Percentage of Oxygen} = \left( \frac{0.288 \, \text{g}}{0.48 \, \text{g}} \right) \times 100 \] Calculating this gives: \[ \text{Percentage of Oxygen} = \left( 0.6 \right) \times 100 = 60\% \] ### Step 4: Present the final results - Percentage composition of Boron = 40% - Percentage composition of Oxygen = 60% Thus, the percentage composition of the compound is: - Boron: 40% - Oxygen: 60%

To find the percentage composition of the compound containing boron and oxygen, we will follow these steps: ### Step 1: Identify the given data - Total mass of the compound = 0.48 g - Mass of boron = 0.192 g - Mass of oxygen = 0.288 g ### Step 2: Calculate the percentage composition of boron ...
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