Match the column I with column II and mark the appropriate choice.
`{:(,"Column I",,"Column II"),((A) ,C_(2)H_(2),(i),sp^(3)d^(2) " hybridisation"),((B),SF_(6),(ii),sp^(3)d^(3)" hybridisation"),((C ),SO_(2),(iii),sp " hybridisation"),((D),IF_(7),(iv),sp^(2)" hybridisation"):}`

Options

A. `(A) to (i), (B) to (iii), (C ) to (ii), (D) to (iv)`
B. `(A) to (iii), (B) to (i), (C ) to (iv), (D) to (ii)`
C. `(A) to (ii), (B) to (iii), (C ) to (i), (D) to (iv) `
D. `(A) to (iv), (B) to (i), (C ) to (iii), (D) to (ii)`

Explanation

To solve the problem of matching the compounds in Column I with their corresponding hybridization states in Column II, we will analyze each compound step by step.

### Step-by-Step Solution:

1. **Identify the Hybridization of IF7 (Iodine Heptafluoride)**:
- Iodine (I) has 7 valence electrons.
- It forms 7 bond pairs with 7 fluorine atoms and has no lone pairs.
- The hybridization can be determined as follows:
- Total orbitals involved = 1s + 3p + 3d = 7 orbitals.
- Therefore, the hybridization of IF7 is **sp³d³**.

2. **Identify the Hybridization of SF6 (Sulfur Hexafluoride)**:
- Sulfur (S) has 6 valence electrons.
- It forms 6 bond pairs with 6 fluorine atoms and has no lone pairs.
- The hybridization can be determined as follows:
- Total orbitals involved = 1s + 3p + 2d = 6 orbitals.
- Therefore, the hybridization of SF6 is **sp³d²**.

3. **Identify the Hybridization of SO2 (Sulfur Dioxide)**:
- Sulfur (S) has 6 valence electrons.
- It forms 2 bond pairs (double bonds with oxygen) and has 1 lone pair.
- The hybridization can be determined as follows:
- Total orbitals involved = 1s + 2p = 3 orbitals.
- Therefore, the hybridization of SO2 is **sp²**.

4. **Identify the Hybridization of C2H2 (Ethyne)**:
- Each carbon (C) has 4 valence electrons.
- In C2H2, each carbon forms 2 bond pairs (one with another carbon and one with hydrogen) and has no lone pairs.
- The hybridization can be determined as follows:
- Total orbitals involved = 1s + 1p = 2 orbitals.
- Therefore, the hybridization of C2H2 is **sp**.

### Matching the Columns:
Now we can match the compounds from Column I with their respective hybridization states from Column II:
- A (C2H2) matches with (iii) sp hybridization.
- B (SF6) matches with (i) sp³d² hybridization.
- C (SO2) matches with (iv) sp² hybridization.
- D (IF7) matches with (ii) sp³d³ hybridization.

### Final Matching:
- A → (iii) sp
- B → (i) sp³d²
- C → (iv) sp²
- D → (ii) sp³d³

### Answer:
The correct option is **B**.