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Strongest bond is (a) HF (b) HCl (c) HB...

Strongest bond is (a) HF (b) HCl (c) HBr (d) HI

A

HF

B

HCl

C

HBr

D

HI

Text Solution

AI Generated Solution

The correct Answer is:
To determine which bond is the strongest among HF, HCl, HBr, and HI, we can analyze the bond strength based on the properties of the elements involved. ### Step-by-Step Solution: 1. **Identify the Bonds**: The question provides four compounds: HF (hydrogen fluoride), HCl (hydrogen chloride), HBr (hydrogen bromide), and HI (hydrogen iodide). Each of these compounds consists of a hydrogen atom bonded to a halogen atom. 2. **Consider the Halogens**: The halogens in these compounds are fluorine (F), chlorine (Cl), bromine (Br), and iodine (I). These elements are in Group 17 of the periodic table. 3. **Analyze Atomic Size**: As we move down the group from fluorine to iodine, the size of the atoms increases. Fluorine is the smallest halogen, while iodine is the largest. 4. **Bond Length and Strength**: Generally, shorter bonds are stronger. Since HF has the smallest atomic size (due to fluorine being the smallest halogen), it forms a shorter and stronger bond with hydrogen compared to the other compounds. 5. **Bond Strength Trend**: The bond strength decreases as the size of the halogen increases. Therefore, the order of bond strength from strongest to weakest is: - HF > HCl > HBr > HI 6. **Conclusion**: Based on the analysis, HF has the strongest bond among the given options. ### Final Answer: The strongest bond is (a) HF. ---
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Knowledge Check

  • The strongest bond is present in

    A
    `Br_(2)`
    B
    `I_(2)`
    C
    `Cl_(2)`
    D
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