The varous types of hydrides and examples of each type are given below :
`{:(,"Hydride type",,"Compound"),((A),"Electron deficient",(i),LiH),((B),"Saline",(ii),CH_(4)),((C ),"Electron-precise",(iii),NH_(3)),((D),"Interstitial",(iv),B_(2)H_(6)),((E ),"Electron rich",(v),CrH):}`
Choose the correct matching from the codes given below :

Options

A. (A) - (ii), (B) - (iv), (C )-(v), (D)-(iii), (E )-(i)
B. (A) - (iv), (B)-(i), (C )-(ii), (D)-(v), (E )-(iii)
C. (A) -(iv), (B) - (iii), (C )-(v), (D)-(ii), (E )-(i)
D. (A)-(v), (B)-(iii), (C )-(iv), (D )-(ii), (E )-(i)

Explanation

To solve the question regarding the various types of hydrides and their corresponding examples, we will analyze each type of hydride and match it with the correct compound.

### Step-by-Step Solution:

1. **Identify the Types of Hydrides:**
- A: Electron deficient
- B: Saline
- C: Electron precise
- D: Interstitial
- E: Electron rich

2. **Identify the Examples Given:**
- (i) LiH
- (ii) CH₄
- (iii) NH₃
- (iv) B₂H₆
- (v) CrH

3. **Match Each Type of Hydride with the Correct Example:**
- **A: Electron deficient** - This type of hydride has fewer electrons than needed for a stable bond. An example is **B₂H₆ (Diborane)**, which is known for being electron deficient. **Match: A → (iv) B₂H₆.**

- **B: Saline** - Saline hydrides are ionic compounds formed with alkali metals. An example is **LiH (Lithium Hydride)**, which is a typical saline hydride. **Match: B → (i) LiH.**

- **C: Electron precise** - These hydrides have the exact number of electrons required to form stable covalent bonds. An example is **CH₄ (Methane)**, which has four electrons forming four covalent bonds. **Match: C → (ii) CH₄.**

- **D: Interstitial** - Interstitial hydrides are formed when hydrogen atoms occupy interstitial sites in a metal lattice. An example is **CrH (Chromium Hydride)**. **Match: D → (v) CrH.**

- **E: Electron rich** - Electron-rich hydrides have more electrons than needed for bonding. An example is **NH₃ (Ammonia)**, which has a lone pair of electrons, making it electron-rich. **Match: E → (iii) NH₃.**

4. **Final Matching:**
- A → (iv) B₂H₆
- B → (i) LiH
- C → (ii) CH₄
- D → (v) CrH
- E → (iii) NH₃

### Conclusion:
The correct matching is:
- A → (iv)
- B → (i)
- C → (ii)
- D → (v)
- E → (iii)