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All members of groups 14 when heated in ...

All members of groups 14 when heated in oxygen form oxides. Which of the following is the correct trend of oixdes?

A

Dioxides `CO_(2), SiO_(2)` and `GeO_(2)` are acidic while `SnO_(2)` and `PbO_(2)` are amphoteric

B

CO,GeO, SnO and PbO are amphoteric

C

Monoxides react with haemoglobin to form toxic compounds.

D

All oxides burn with blue flame.

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct trend of oxides formed by the members of Group 14 when heated in oxygen, we need to analyze the nature of the oxides produced by each element in this group. The elements in Group 14 include Carbon (C), Silicon (Si), Germanium (Ge), Tin (Sn), and Lead (Pb). ### Step-by-Step Solution: 1. **Identify the Oxides**: - Carbon forms Carbon Dioxide (CO2). - Silicon forms Silicon Dioxide (SiO2). - Germanium forms Germanium Dioxide (GeO2). - Tin forms Tin Dioxide (SnO2). - Lead forms Lead Dioxide (PbO2). 2. **Determine the Nature of Each Oxide**: - **Acidic Oxides**: - CO2 is acidic because it reacts with bases to form salts (e.g., Na2CO3). - SiO2 is also acidic and reacts with strong bases (e.g., NaOH) to form silicates (e.g., Na2SiO3). - GeO2 is acidic as well and behaves similarly to SiO2. - **Amphoteric Oxides**: - SnO2 and PbO2 are amphoteric, meaning they can react with both acids and bases. For example, SnO2 can react with HCl to form SnCl4 and water, and it can also react with bases to form salts. 3. **Summarize the Trends**: - The trend in the nature of oxides from acidic to amphoteric is as follows: - CO2 (acidic) → SiO2 (acidic) → GeO2 (acidic) → SnO2 (amphoteric) → PbO2 (amphoteric). 4. **Conclusion**: - The correct trend of oxides in terms of their acidic or amphoteric nature is that the oxides of Carbon, Silicon, and Germanium are acidic, while the oxides of Tin and Lead are amphoteric.
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Knowledge Check

  • Which of the following is not the correct grouping?

    A
    Ectoderm-Retina, epidermis and nervous system
    B
    Mesoderm-Ovary, urinary bladder and kidneys
    C
    Mesoderm-kidneys, connective tissue and testis
    D
    Endoderm-Thyroid, pineal and thymus.
  • For the electrons of oxygen atom, which of the following statements correct?

    A
    `Z_(eff)` for an electron in a 2s orbital is the same as `Z_(eff)` for an electron in a 2p orbital.
    B
    An electron in the 2s orbital has the same energy as an electron in the 2p orbital.
    C
    `Z_(eff)` for an electron in 1s orbital is the same as `Z_(eff)` for an electron in a 2s orbital.
    D
    The two electrons present in the 2s orbital have spin quantum numbers, `m_(s)` but of opposite sign.
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