Home
Class 12
CHEMISTRY
The reaction , RCl + NaI overset(" Dry...

The reaction , ` RCl + NaI overset(" Dry acetone")to R - I + NaCl` is known as

A

Wurtz reaction

B

Fitting reaction

C

Wurtz-Fitting reaction

D

Finkelstein's reaction .

Text Solution

AI Generated Solution

The correct Answer is:
To determine the name of the reaction represented by the equation \( RCl + NaI \overset{\text{Dry acetone}}{\rightarrow} R-I + NaCl \), we can analyze the components and the type of reaction taking place. ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: - The reactants are \( RCl \) (an alkyl chloride) and \( NaI \) (sodium iodide). - The products are \( R-I \) (an alkyl iodide) and \( NaCl \) (sodium chloride). 2. **Understand the Reaction Conditions**: - The reaction occurs in the presence of dry acetone, which is a polar aprotic solvent. This solvent helps facilitate the nucleophilic substitution reaction. 3. **Recognize the Type of Reaction**: - The reaction involves the substitution of the chlorine atom in \( RCl \) with an iodine atom from \( NaI \). This is characteristic of a nucleophilic substitution reaction. 4. **Name the Reaction**: - This specific type of nucleophilic substitution, where an alkyl halide is converted to another alkyl halide (in this case, from chloride to iodide), is known as the **Finkelstein reaction**. 5. **Conclusion**: - Therefore, the reaction \( RCl + NaI \overset{\text{Dry acetone}}{\rightarrow} R-I + NaCl \) is known as the **Finkelstein reaction**.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • PRACTICE PAPER -2

    NCERT FINGERTIPS ENGLISH|Exercise Practice Paper 2|50 Videos
  • PRACTICE PAPER -1

    NCERT FINGERTIPS ENGLISH|Exercise Practice Paper 1|50 Videos
  • PRACTICE PAPER -3

    NCERT FINGERTIPS ENGLISH|Exercise Practice Paper 3|50 Videos

Similar Questions

Explore conceptually related problems

Consider the following reaction Glucose overset("Reagent")rarr"Mannose" The above reaction is known as

Identify X in the reaction HCHO + CH_(3)Mgloverset("dry ether")to "Intermediate" overset(H_(2) "O"//H^(+)) to X :

Knowledge Check

  • Statement - 1 : CH_(3) - CH_(2) - Cl + Nal overset("Acetone") rarr CH_(3) - CH_(2) - I + NaCldarr Statement- 2 : Acetone is polar-protic solvent and solubility order of sodium halides decreases dramatically in order Nal > NaBr > NaCl. The last being virtually insoluble in this solvent and a 1^(@) and 2^(@) chloro alkane in acetone is completely driven to the side of Iodoalkane by the precipitation reaction.

    A
    Statement-1 is true, Statement-2 is true and Statement-2 is correct explanation for statement-1.
    B
    Statement-1 is true, Statement-2 is true and Statement-2 is Not the correct explanation for statement-1.
    C
    Statement-1 is true, Statement-2 is false.
    D
    Statement-1 is false, Statement-2 is true.
  • 1-4-dichlorohexane (1 mole) + NaI (1 mole) overset("Acetone") rarr Product of the reaction is :

    A
    `Cl - CH_2-CH_2 - underset(I)underset(|)CH-CH_2-CH_3`
    B
    `I - CH_2 - CH_2 - underset(Cl)underset(|)CH-CH_2 -CH_3`
    C
    `H_2C=CH-underset(Cl)underset(|)CH-CH_2-CH_3`
    D
    `I - CH_2-CH_2 - CH_2 underset(Cl)underset(|)CH-CH_2-CH_3`
  • Similar Questions

    Explore conceptually related problems

    (CH_(3))_(2)CHCl+NaI overset("Acetone")rarr (CH_(3))_(2)CHI+NaCl The above reaction is known as :

    CH_(3)-CH_(2)-CI+NaI overset("Dry acetone")rarr [X]+NaCI Product [X] is -

    The rate law for the reaction RCl + NaOH(aq) rarr ROH + NaCl is given by Rate = k[RCl] . The rate of the reaction will be

    Consider the following route of reaction: R_(2)SiCl_(2)+"water" to (A) overset("Polymerisation")to (B) Compound(B) in above reaction is:

    Assertion (A): For the reaction RCl + NaOH(g) rarr ROH + NaCl , the rate of reaction is reduced to half on reducing the cocentration of RCl to half. Reason (R ): The rate of the reaction is represented by k[RCl] , i.e., it is a first order reaction.

    CH_3-Cl+NaI overset("Acetone")iff CH_3-I+NACl Above equilibrium is more towards right because