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Calculate the mass of ascorbic acid (Mol...

Calculate the mass of ascorbic acid (Molar mass = 176 g `mol^(-1)`) to be dissolved in 75 g of acetic acid, to lower its freezing point by `1.5^(@)C. [K_(f)=3.9"K kg mol"^(-1)]`

Text Solution

Verified by Experts

Apply the relation
`M_(2)=(K_(f)xx w_(2) xx 1000)/(DeltaT_(f) xx w_(1))`
Given: `K_(f)=3.9"K kg mol"^(-1), M_(2)=176" g mol"^(-1), DeltaT_(f)=1.5""^(@)C, w_(1)=75g`
Substituting the values in the equation above, we have
`176" g mol"^(-1)=(3.9"K kg mol"^(-1) xx w_(2) xx 1000)/(1.5K xx 75g)`
or `w_(2)=(176"g mol"^(-1)xx1.5K xx 75g)/(3.9"K kg mol"^(-1) xx 1000"g kg"^(-1))`
`=(176xx1.5xx75)/(3.9xx1000)=5.077g`
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Knowledge Check

  • The mass of ascorbic acid (C_(6)H_(8)O_(6)) to be dissolved in 100g of acetic acid to lower its freezing point by 1.5^(@)C in g is : ( K_(f) for acetic acid is "4.0 K kg mol"^(-1) )

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    B
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    C
    6.6
    D
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  • How much polystrene of molar mass 9000 g mol ^(-1) would have to be dissolved in 100 g of C_(6) H_(6) to lower its freezing point by 1.05 K ?

    A
    19.3g `
    B
    `193 g `
    C
    `38.6 g `
    D
    `77.2g`

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