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Two point charges are separated by some distance, repel each other with a force F. What will be the force if distance between them is halved?

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Knowledge Check

  • A system of two charges separated by a certain distance apart stores electrical potential energy. If the distance between them is increased, the potential energy of the system,

    A
    may increase or decrease
    B
    increases in any case
    C
    remains the same
    D
    decreases in any case

  • Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of replulsion between the ions, the number of electrons missing from each ion will be : (e being the charge on an electron)

    A
    `(4piepsilon_(0)Fd^(2))/(e^(2))`
    B
    `(4piepsilon_(0)Fd^(2))/(e^(2))`
    C
    `sqrt((4piepsilon_(0)Fe^(2))/(d^(2)))`
    D
    ` sqrt((4piepsilon_(0)Fd^(2))/(e^(2)))`

  • Two positive point charges Q and 4Q are separted by a distance of 12 cm and from each other. The distance of the neutral point from Q is

    A
    12 cm
    B
    6 cm
    C
    8 cm
    D
    4 cm

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    Two balls carrying charges of +3muC and -3 muC attract each other with a force F. If charge +3muC is added to both, the force between the balls will be :

    Two electrically charged particles , having charges of different magnitudes , when placed at a distance 'd' from each other , experience a force of attraction 'F' . These two particles are put in contact and again placed at the same distance from each other. What is the nature of new force between them ?

    a. Two insulated charged copper spheres A and B have their centres separated by a distance o 0.5 m. What is the mutual force of electrostatic repulsion if the charge on each is 6.5xx10^(-7)C ? Assume that the radii of A and B are negligible compared to the distance fof separation. b. What is the fore of repulsion if each sphere is charged double the above amount and the distance between them is halved?

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