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{:("Column-I","Column-Il"),("A) Thermal ...

`{:("Column-I","Column-Il"),("A) Thermal stress,","P)" 3 alpha Delta t (100) ),("B) Loss in time of a pendulum clock per sec.","Q)" (d)/( ( alpha_(2) - alpha_(1) ) Delta t) ),("C) Percentage in volume of a solid","R)" Y alpha Delta t ),("D) Radius of circular arc of a bimetal strip","S)" (1//2) alpha Delta t):}`

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The correct Answer is:
A-R; B-S; C-P; D-Q
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S.T tan alpha =(sin 2 alpha )/(1+cos 2 alpha ) . Hence find the value of tan 15^(@) and tan 22 1//2^(@)

Knowledge Check

  • If A ( cos alpha, sin alpha ), B (sin alpha - cos alpha ), C( 1, 2 ) are the vertices of a Delta ABC , then the locus of its centroid is

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    B
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    C
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    D
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  • The relation time 1 and distance x is t= alpha x^(2) beta x . Where alpha and beta are constants. The retardation is

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    B
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    `2 alpha beta v^(3)`
    D
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  • If alpha, beta, gamma, delta are roots of x^(3) - 4x^(2) - x + 2 = 0 then sum (1)/(alpha^(2)) =

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    Whenever a liquid is heated in a container, expansion of liquid as well as container lakes place. If gamma is the coefficient of volume expansion of the liquid and alpha is the coefficient of volume expansion of the container. {:("Column-I","Column-II"),("A)Liquid level raises with respect to container.","P)" gamma=2alpha),("B) Liquid level remains same with respect to container.","Q)" gamma lt 3 alpha),("C) Liquid level drops with respect to container.","R)" gamma= 3 alpha),("D)Liquid level remains same with respect to ground.","S)" gamma gt 3 alpha):}

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