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Step by step text solution for What is the radius of the path of an electron (mass 9 × 10-31 kg and charge 1.6 ×x 10^(–19) C) moving at a speed of 3 ×x10^7 m/s in a magnetic field of 6 x× 10^(-4) T perpendicular to it? What is its frequency? Calculate its energy in keV. (1eV = 1.6 xx 10^(-19) J) by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.
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