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For the wave y = 5 sin 30 pi [t -(x//240...

For the wave `y = 5 sin 30 pi [t -(x//240)]`, where x and y are in cm and t is in seconds, find the
Displacement when t = 0 and x = 2cm

Text Solution

Verified by Experts

`-3.535 cm`
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Knowledge Check

  • The equation of a wave is y= 4 sin[pi/2 (2t + 1/8x)] where y and x are in cm and t is in second.

    A
    The amplitude, wavelength, velocity and frequency of wave are 4cm, `16cm,32cm^(-1)` and 1Hz respectively with wave propagating along + x direction,
    B
    The amplitude, wavelength, velocity and frequency of wave are 4cm, 32cm, 16cm/s, and 0.5Hz respectively with wave propagating along -x direction
    C
    Two position occupied by the particle at time interval of 0.4s have a phase difference of `0.4 pi` radian
    D
    Two position occupied by the particle at separation of 12 cm have a phase difference of 135°

  • The equation of a wave is y= 4sin [pi/2 (2t + 1/8 x)] where, y and x are in cm and t is in second

    A
    The amplitude, wavelength, velocity and frequency of wave are `4cm, 16cm,32cm^(-1)` and 1Hz respectively with wave propagating along + x direction
    B
    The amplitude, wavelength, velocity and frequency of wave are 4cm, 32cm, 16cm/s, and 0.5Hz respectively with wave propagating along -x direction
    C
    Two position occupied by the particle at time interval of 0.4s have a phase difference of 0.4`pi` radian
    D
    Two position occupied by the particle at separation of 12 cm have a phase difference of `135^@`

  • A stationary wave is given by y = 5 sin (pi x)/(3) cos 40 pi t where x and y are in cm and t is in seconds What is the distance between two successive nodes

    A
    0.01m
    B
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    C
    0.03m
    D
    0.04m

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