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If for Ag|Ag((0.01M))^(+)||Ag((0.1M)^(+)...

If for `Ag|Ag_((0.01M))^(+)||Ag_((0.1M)^(+)|Ag,` cell `E_(Ag^(+)|Ag)^(@)=0.80V`, then . . .

A

`E_(cell)^(@)=0.80V`

B

`E_(cell)=0.0296V`

C

Cell will not work as both electrodes are same

D

`E_(cell)=0.059V`

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(cell)=E_(cell)^(@)-(0.059)/(n)"log"(0.01)/(0.1)`
`=-0.059xx(-1.0)`
`=0.059V`
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