Home
Class 12
PHYSICS
Given two vectors vec(A)=3hat(i)+4hat(j)...

Given two vectors `vec(A)=3hat(i)+4hat(j)` and `vec(B)=hat(i)+hat(j).theta` is the angle between `vec(A)` and `vec(B)`. Which of the following statements is/are correct?

A

`|vecA|costheta((hati+hatj)/(sqrt(2)))` is the component of `vecA ` along `vecB` .

B

`|vecA|sintheta((hati-hatj)/(sqrt(2)))` is the component of `barA` perpendicular to `vecB`

C

`|vecA|costheta((hati-hatj)/(sqrt(2)))` is the component of `vecA` along `barB` .

D

`|vecA|sintheta((hati+hatj)/(sqrt(2)))` is the component of `vecA` perpendicular to `vecB` .

Text Solution

Verified by Experts

The correct Answer is:
A, B

Component of `vecA` along `vecB` is `|vecA| cos theta hatB` for `theta` being the angle between the vectors. Also `hatB= (hati+hatj)/(sqrt(2))` . So choice (a) is correct.
The vector `( hati-hatj)` is perpendicular to the vector `(hati+hatj)`
So the other resolved component is
`|vecA|sin theta= ((hati-hatj)/(sqrt(2)))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 1 : Single Option Correct Type (1 Mark) )|9 Videos
  • KINEMATICS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 3 : One or More than One Option Correct Type (2 Marks) )|1 Videos
  • KINEMATICS

    MTG-WBJEE|Exercise WB JEE WORKOUT ( CATEGORY 2 : Single Option Correct Type (2 Marks))|15 Videos
  • HEAT AND THERMAL PHYSICS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS|15 Videos
  • KINETIC THEORY OF GASES

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (MCQ)|7 Videos

Similar Questions

Explore conceptually related problems

If vec(a) = 5 hat(i) - hat(j) - 3 hat(k) and vec(b) = hat(i) + 3 hat(j) - 5 hat(k) , find the angle between vec(a) and vec(b) .

If vec(A)=2hat(i)+3hat(j)-hat(k) and vec(B)=-hat(i)+3hat(j)+4hat(k) , then find the projection of vec(A) on vec(B) .

Knowledge Check

  • Give two vectors vec(A)==3hat(i)+4hat(j) and vec(B)=hat(i)+hat(j).theta is the angle between vec(A) and vec(B) . Which of the following statements is/are correct?

    A
    `|vec(A)|cos theta((hat(i)+hat(j))/(sqrt(2)))` is the component of `vec(A)` along `vec(B)`.
    B
    `|vec(A)|sin theta((hat(i)-hat(j))/sqrt(2))` is the component of `vec(A)` perpendicular to `vec(B)`.
    C
    `|vec(A)|cos theta((hat(i)-hat(j))/(sqrt(2)))` is the component of `vec(A)` along `vec(B)`.
    D
    `|vec(A)|sin theta((hat(i)+hat(j))/(sqrt(2)))` is the component of `vec(A)` perpendicular to `vec(B)`.
  • The angle between the two vector vec(A)= 5hat(i)+5hat(j) and vec(B)= 5hat(i)-5hat(j) will be

    A
    Zero
    B
    `45^(@)`
    C
    `90^(@)`
    D
    `180^(@)`
  • Given vec(A) = 3hat(i) + 2hat(j) and vec(B) = hat(i) + hat(j). The component of vector vec(A) along vector vec(B) is

    A
    `(1)/(sqrt2)`
    B
    `(3)/(sqrt2)`
    C
    `(5)/(sqrt2)`
    D
    `(7)/(sqrt2)`
  • Similar Questions

    Explore conceptually related problems

    If vec(A) = 3 hat(i) - 4 hat(j) and vec(B) = 2 hat(i) + 16 hat(j) then the magnitude and direction of vec(A) + vec(B) will be

    The angle between two vectors vec(A)= 3hat(i)+4hat(j)+5hat(k) and vec(B)= 3hat(i)+4hat(j)+5hat(k) is

    Given two vectors vec(A) = -hat(i) + 2hat(j) - 3hat(k) and vec(B) = 4hat(i) - 2hat(j) + 6hat(k) . The angle made by (A+B) with x-axis is :

    If vec(a)=(hat(i)+2hat(j)-3hat(k)) and vec(b)=(3hat(i)-hat(j)+2hat(k)) then the angle between (vec(a)+vec(b)) and (vec(a)-vec(b)) is

    vec(A) and vec(B) are two vectors given by vec(A)=2hat(i)+3hat(j) and vec(B)=hat(i)+hat(j). The magnitude of the component of vec(A) along vec(B) is