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Find moles of electrons present in 64 g ...

Find moles of electrons present in 64 g of ` CH_4`

A

64

B

40

C

24

D

16

Text Solution

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The correct Answer is:
To find the moles of electrons present in 64 g of CH₄ (methane), we can follow these steps: ### Step 1: Calculate the molar mass of CH₄ The molar mass of CH₄ can be calculated by adding the atomic masses of carbon (C) and hydrogen (H): - Atomic mass of Carbon (C) = 12 g/mol - Atomic mass of Hydrogen (H) = 1 g/mol Since there are 4 hydrogen atoms in CH₄, the calculation is: \[ \text{Molar mass of CH₄} = 12 \, \text{g/mol (C)} + 4 \times 1 \, \text{g/mol (H)} = 12 + 4 = 16 \, \text{g/mol} \] ### Step 2: Calculate the number of moles of CH₄ in 64 g Using the formula: \[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] we can find the number of moles of CH₄: \[ \text{Number of moles of CH₄} = \frac{64 \, \text{g}}{16 \, \text{g/mol}} = 4 \, \text{moles} \] ### Step 3: Determine the number of electrons in CH₄ In CH₄, each carbon atom shares electrons with four hydrogen atoms. The total number of electrons contributed by each atom is: - Carbon (C) contributes 4 valence electrons. - Each Hydrogen (H) contributes 1 valence electron. Thus, the total number of electrons in one molecule of CH₄ is: \[ \text{Electrons in CH₄} = 4 \, \text{(from C)} + 4 \times 1 \, \text{(from H)} = 4 + 4 = 8 \, \text{electrons} \] ### Step 4: Calculate the total number of electrons in 4 moles of CH₄ To find the total number of electrons in 4 moles of CH₄, we can use Avogadro's number (approximately \(6.022 \times 10^{23}\) molecules/mol): \[ \text{Total number of molecules in 4 moles} = 4 \, \text{moles} \times 6.022 \times 10^{23} \, \text{molecules/mol} = 2.4088 \times 10^{24} \, \text{molecules} \] Now, we multiply the number of molecules by the number of electrons per molecule: \[ \text{Total electrons} = 2.4088 \times 10^{24} \, \text{molecules} \times 8 \, \text{electrons/molecule} = 1.92704 \times 10^{25} \, \text{electrons} \] ### Final Answer The total number of moles of electrons present in 64 g of CH₄ can be calculated by dividing the total number of electrons by Avogadro's number: \[ \text{Moles of electrons} = \frac{1.92704 \times 10^{25} \, \text{electrons}}{6.022 \times 10^{23} \, \text{electrons/mol}} \approx 32 \, \text{moles of electrons} \]
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Knowledge Check

  • Total number of valence electrons present in 6.4 gm of peroxide ion O_(2)^(-2) is -

    A
    `2.8 N_(A)`
    B
    `3.2 N_(A)`
    C
    `0.2 N_(A)`
    D
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  • How many millimoles of methane, CH_(4) are present in 6.4 g of this gas?

    A
    0.4
    B
    4
    C
    40
    D
    `4.0 xx 10^(2)`
  • The no of electrons present in one mole of Azide ion are (N_(3)^(-))

    A
    21 N
    B
    20N
    C
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    D
    43N
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