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For an equilibrium reaction, if the valu...

For an equilibrium reaction, if the value of standard Gibb's free energy, AG° is zero, then the value of equilibrium constant, K will be equal to

A

Zero

B

2

C

1

D

10

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • For the equilibrium reaction, the value of Gibbs free energy change is:

    A
    `gt0`
    B
    `lt0`
    C
    `=0`
    D
    `ne0`
  • The standard Gibb's free energy change, DeltaG^(@) is related to equilibrium constant, kp as

    A
    `Kp=-Rt ln Delta H^(@)`
    B
    `Kp=[e/(RT)]^(DeltaG^(@))`
    C
    `Kp=-(Delta G)/(RT)`
    D
    `Kp=e^(-DeltaG^(@)//RT)`
  • The standard Gibbs free energy change DeltaG^(@) is related to equilibrium constant K_(p) as

    A
    `K_(p)=-RTlnDeltaG^(@)`
    B
    `K_(p)=((e)/(RT))^(DeltaG^(@))`
    C
    `K_(p)=-(DeltaG^(@))/(RT)`
    D
    `K_(p)=e^(-(DeltaG^(@))/(RT))`
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