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If a non-volatile solute is dissolved in...

If a non-volatile solute is dissolved in a volatile solvent relative lowering of vapour pressure is equal to

A

Moles of solute

B

Moles of solvent

C

Mole fraction of solute

D

Mole fraction of solvent

Text Solution

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The correct Answer is:
To solve the question regarding the relative lowering of vapor pressure when a non-volatile solute is dissolved in a volatile solvent, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Vapor Pressure**: - Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid phase. When a non-volatile solute is added to a volatile solvent, the vapor pressure of the solvent decreases. 2. **Defining Relative Lowering of Vapor Pressure**: - The relative lowering of vapor pressure (RLVP) is defined as the decrease in vapor pressure of the solvent when a solute is added, compared to the original vapor pressure of the pure solvent. 3. **Using Raoult's Law**: - According to Raoult's Law, the vapor pressure of a solution (P_solution) is directly proportional to the mole fraction of the solvent (X_solvent): \[ P_{\text{solution}} = X_{\text{solvent}} \cdot P^0_{\text{solvent}} \] - Where \(P^0_{\text{solvent}}\) is the vapor pressure of the pure solvent. 4. **Calculating Relative Lowering**: - The relative lowering of vapor pressure can be expressed as: \[ \text{Relative Lowering} = \frac{P^0_{\text{solvent}} - P_{\text{solution}}}{P^0_{\text{solvent}}} \] - Substituting for \(P_{\text{solution}}\) from Raoult's Law: \[ \text{Relative Lowering} = \frac{P^0_{\text{solvent}} - (X_{\text{solvent}} \cdot P^0_{\text{solvent}})}{P^0_{\text{solvent}}} \] - This simplifies to: \[ \text{Relative Lowering} = \frac{P^0_{\text{solvent}}(1 - X_{\text{solvent}})}{P^0_{\text{solvent}}} = 1 - X_{\text{solvent}} \] 5. **Relating to Mole Fraction of Solute**: - Since the sum of the mole fractions of solute and solvent is 1, we have: \[ X_{\text{solute}} = 1 - X_{\text{solvent}} \] - Therefore, the relative lowering of vapor pressure can also be expressed in terms of the mole fraction of the solute: \[ \text{Relative Lowering} = X_{\text{solute}} \] 6. **Conclusion**: - The relative lowering of vapor pressure when a non-volatile solute is dissolved in a volatile solvent is equal to the mole fraction of the solute. ### Final Answer: The relative lowering of vapor pressure is equal to the mole fraction of the solute.
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Knowledge Check

  • When a non volatile solute is dissolved in a solvent, the relative lowering in vapour pressure is equal to

    A
    mole fraction of solvent
    B
    mole fraction of solute
    C
    concentration of solute in `g L^(-1)`
    D
    concentration of solute in g per100 mL
  • Addition of a non-volatile solute in a volatile ideal solvent

    A
    Increases the vapoure pressure of the solvent Decreases the vapour pressure of the solvent
    B
    Decreases the vapoure pressure of the solvent
    C
    Decreases the boililng point of the solvent
    D
    Increases the freezing point of the solvent
  • When non-volatile solute is assed to a pure solvent, the:

    A
    vapour pressure of the solution becomes lower than the vapour pressure of the pure solvent
    B
    rate of evaporation of solvent is reduced
    C
    solute does not affect the rate of condensation
    D
    none of these
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