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Power Gain of CE amplifier circuit is gi...

Power Gain of CE amplifier circuit is given by

A

Voltage gain × current gain

B

Voltage gain/Current gain

C

Current gain/Voltage gain

D

(Voltage gain)^2 × current gain

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The correct Answer is:
To determine the power gain of a Common Emitter (CE) amplifier circuit, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Common Emitter Configuration:** - The Common Emitter (CE) configuration is a type of transistor amplifier where the emitter terminal is common to both the input and output circuits. This configuration can be used with both NPN and PNP transistors. 2. **Define Power Gain:** - Power Gain (denoted as \( P_G \)) is defined as the ratio of the output power (\( P_{out} \)) to the input power (\( P_{in} \)). \[ P_G = \frac{P_{out}}{P_{in}} \] 3. **Relate Power to Voltage and Current:** - Power can be expressed in terms of voltage and current. The power in an electrical circuit is given by: \[ P = V \times I \] - Therefore, we can express the output power and input power as: \[ P_{out} = V_{out} \times I_{out} \] \[ P_{in} = V_{in} \times I_{in} \] 4. **Express Power Gain in Terms of Voltage and Current Gain:** - The voltage gain (\( A_V \)) is defined as the ratio of output voltage to input voltage: \[ A_V = \frac{V_{out}}{V_{in}} \] - The current gain (\( A_I \)) is defined as the ratio of output current to input current: \[ A_I = \frac{I_{out}}{I_{in}} \] 5. **Combine the Gains to Find Power Gain:** - By substituting the expressions for power into the power gain formula, we get: \[ P_G = \frac{V_{out} \times I_{out}}{V_{in} \times I_{in}} = A_V \times A_I \] - Thus, the power gain of a Common Emitter amplifier can be expressed as: \[ P_G = A_V \times A_I \] 6. **Conclusion:** - The formula for the power gain of a Common Emitter amplifier circuit is given by the product of its voltage gain and current gain.
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Knowledge Check

  • Transconductance in CE amplifier circuit is defined as

    A
    Ratio of change in collector current to the change in emitter current
    B
    Ratio of change in input base-emitter voltage to the change in emitter current
    C
    Ratio of change in collector current to the change in input base-emitter voltage
    D
    Ratio of change in emitter current to the change in input base-emitter voltage
  • A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Omega is connected in the collector circuit and the voltage drop across it is 0.8 V . If the current amplification factor is 0.96 and the input resistance of the circuit is 192 Omega , the voltage gain and the power gain of the amplifier will respectively be

    A
    `4,3.69`
    B
    `4, 3.84`
    C
    `3.69, 3.84`
    D
    `4, 4`
  • A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Omega is connected in the collector circuit and the voltage drop across 0.96 and the input resistance of the circuit is 192 Omega , the voltage gain and the power gain of the amplifier will respectively be :

    A
    `4,3.84`
    B
    `3.69,3.84`
    C
    `4,4`
    D
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