Home
Class 11
MATHS
Find the angle between the cures given b...

Find the angle between the cures given below : `x^(2)+3y=3, x^(2)-y^(2)+25=0`

Text Solution

Verified by Experts

The correct Answer is:
`Tan^(-1)((22(sqrt6))/(69))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • TANGENT AND NORMAL

    AAKASH SERIES|Exercise ADVANCED SUBJECTIVE TYPE QUESTIONS|48 Videos

  • TANGENT AND NORMAL

    AAKASH SERIES|Exercise EXERCISE 7.2 (SHORT ANSWER & LONG ANSWER QUESTIONS)|7 Videos

  • STRAIGHT LINES

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL-II (ADVANCED) PRACTICE SHEET (ADDVANCED)) (Comprehension Type Questions)|6 Videos

  • TRANSFORMATIONS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-I LEVEL-I Straight Objective Type Questions)|41 Videos

Similar Questions

Explore conceptually related problems

Find the angle between the curves given below. x^(2)+3y=3,x^(2)-y^(2)+25=0 .

Find the angle between the cures given below : y^(2)=8x, 4x^(2)+y^(2)=32

Find the angle between the curves given below. y^(2)=4x, x^(2)+y^(2)=5 .

Find the angle between the curves given below. y^(2)=8x, 4x^(2)+y^(2) =32 .

Find the angle between the curves given below. x^(2)y=4, y(x^(2)+4)=8 .

Find the angle between the curves given below. x+y+2=0,x^(2)+y^(2)-10y=0 .

Find the angle between the cures given below : x^(2)=2(x+1), y=(8)/(x^(2)+4)

Find the angle between the curves given below. x^(2)=2(y+1), y=(8)/(x^(2)+4) .

Find the angle between the curves given below. 2y^(2)-9x=0, 3x^(2)+4y=0 (in the 4^("th") quadrant).

Find the angle between the curve and line given below : 2y-9x=0, 3x^(2)+4y=0 (in the 4^(th) quadrant)

Home
Profile