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In DeltaOAB, E is the midpoint of AB and...

In `DeltaOAB`, E is the midpoint of AB and F is a point on OA such that OF = 2FA. If C is the point of intersection of `bar(OE) and bar(BF)`, then find the ratios OC : CE and BC : CF.

Text Solution

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The correct Answer is:
`OC:CE=4:1, BC:CF=3:2`
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Explore conceptually related problems

If Delta OAB E is the mid point of AB and F is a point on OA such that OF = 2 (FA) if C is the point of intersection of bar(OE) and bar (BF) then find the rations OC : CE and BC : CF

In DeltaOAB,E is the midpoint of AB and F is a point on OA such that bar(OF)=2bar(FA). If C is the point of intersection of OE and BF , then find the ratio 's OC:CE and BC:CF

Knowledge Check

  • In DeltaOAB , E is the mid point of AB and F is a point on OA such that OF=2FA. If C is the point of intersection of OE and BF, then find the ratios OC : CE and BC : CF are

    A
    `1:4, 3:2`
    B
    `4:1, 3:2`
    C
    `4:1, 1:2`
    D
    `4:1, 2:3`

  • In a DeltaOAB, E is the mid point of OB and D is a point in AB such that AD : DB = 2 : 1. If OD and AE intersect at P, then OP : PD =

    A
    `3:2`
    B
    `2:3`
    C
    `1:4`
    D
    `4:1`

    • Similar Questions

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