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The period of tan theta+ tan (theta+(pi)...

The period of `tan theta+ tan (theta+(pi)/(3)) +tan (theta+(2pi)/(3))` is

A

`(pi)/(2)`

B

`pi`

C

`2pi`

D

`(pi)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • If tan theta + tan ( theta + (pi)/(3))+ tan ( theta + (2pi)/(3))=3 , then which of the following is equal to 1 ?

    A
    ` tan 2 theta `
    B
    `tan 3 theta `
    C
    `tan^(2) theta `
    D
    `tan^(3) theta `
  • The period of (tan theta -1/3 tan ^(3) theta ) ((1)/(3) - tan ^(2) theta ), when tan ^(2) theta ne 1/3 is

    A
    `pi/3`
    B
    `(2pi)/(3)`
    C
    `pi`
    D
    `2pi`
  • The period of ( tan theta -(1)/(3) tan^(3) theta ) ((1)/(3) - tan^(2) theta )^(-1), where tan^(2) theta ne (1)/(3) is :

    A
    `(pi)/(3) `
    B
    `(2pi)/(3) `
    C
    `pi`
    D
    `2pi`
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    Observe the following statements : A : If sin h^(-1)sqrt(3) = log_(e)(sec theta + tan theta) , then theta = (pi)/(3) R : If tan theta sqrt(3), sec theta = 2 rArr theta = (pi)/(3) . The the true statement among the following is :

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    cot theta-tan theta - 2 tan 2 theta - 4 tan 4 theta

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