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The average translational kinetic energy...

The average translational kinetic energy of nitrogen gas molecules is 0.02 eV(1 eV = `1.6xx10^(-19)J`). Calculate the temperature of the gas. Boltzmann constant `k=1.38xx10^(-28)J//K`.

A

193.1 K

B

1011 K

C

212 K

D

154.5 K

Text Solution

Verified by Experts

The correct Answer is:
D
Translational K.E. of nitrogen molecule = `(3)/(2)kT`
`(3)/(2)kT=0.02eV=0.02xx1.6xx10^(-19)J`
`T=(0.02xx1.6xx10^(-19))/(1.38xx10^(-23))xx(2)/(3)orT=154.5K`
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