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The r.m.s. speed of oxygen is v at a par...

The r.m.s. speed of oxygen is v at a particular temperature. If the temperature is doubled and oxygen molecule dissociate into oxygen atoms, the r.m.s. speed becomes

A

v

B

`sqrt(2)v`

C

`2v`

D

`4v`

Text Solution

Verified by Experts

The correct Answer is:
C
As, `v_(rms)=sqrt((3RT)/(M))`
For oxygen molecules at temperature T,
`v_(rms)=v=sqrt((3RT)/(M))" "...(i)`
Now, temperature is doubled and oxygen molecules dissociate into oxygen atom (molar mass becomes `M//2`) then rms speed will be
`v._(rms)=sqrt((3R(2T))/((M//2)))=2sqrt((3RT)/(M))=2v` [Using eqn(i)]
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Knowledge Check

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