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a) 24 g of a non-volatile, non-electroly...

a) 24 g of a non-volatile, non-electrolyte solute is added to 600 g of water. The boiling point of the resulting solution is 373.35K. Calculate the molar mass of the solute `("Given boiling point of pure water = 373 K and Kb for water=0.52 K kg mol"^(-1))`.

Text Solution

Verified by Experts

Given
`w_(2)=24g`
`w_(1)=600g`
`DeltaT_(b)=0.35 K`
`m_(2)=?` `"Molar mass of the solute, "M_(2)=(1000KbW_(2))/(DeltaTbxxw_(1))`
`therefore M_(2)="59.42g mol"^(-1)`
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