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An electrolytic cell contains a solution of `Ag_(2)SO_(4)` and platinum electrodes. Current is passed until 1.6 g. of `O_(2)` has been liberated at anode. The amonut of Ag deposited at cathode would be

A

0.8g

B

1.6g

C

21.6g

D

107.88g

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • When dilute H_(2)SO_(4) is electrolysed at room temperature between platinum electrodes, the substance liberated at the anode is

    A
    S
    B
    `SO_(2)`
    C
    `H_(2)`
    D
    `O_(2)`
  • Three Faraday's of electricity are passed through molten Al_2O_3 , aq. solution of CuSO_4 and molten NaCl taken in three different electrolytic cells. The amounts of Al, Cu and Na deposited at the electrodes will be

    A
    1 mole : 2 moles: 3 moles
    B
    1 mole : 1.5 mole: 3 moles
    C
    3 moles: 2 moles: 1 mole
    D
    1 mole : 1.5 mole : 2 moles
  • Electrolysis is the process in which electrical energy is converted to chemical energy. In electrolyte cell, oxidation takes place at anode and reduction at cathode. Electrode process depends on the electrode taken for electrolysis. Amount of substance liberated at an electrode is directly proportionation to the amount of charge passed through it. The mass of substance liberated at electrode is calculate using the following realation : m=(itE)/(96500) Here, E represent the equivalent mass and 96500 C is called the faraday constant. Faraday (96500 C) is the charge of 1 mole electron i.e., 6.023 xx 10^(23) electrons, it is used to liberate on gram equivalent of the substance. The platinum electrodes were immersed in a solution of cupric sulphate (CuSO_4) and electric current is passed through the solution. After sometimes, it was observed that the colour of copper sulphate disappeared with evolution of a gas at the electrode. The colourless solution contains.

    A
    platinum sulphate
    B
    copper nitrate
    C
    copper sulphate
    D
    sulphuric acid
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