Home
Class 12
CHEMISTRY
The hydrogen electrode is dipped in a so...

The hydrogen electrode is dipped in a solution of `pH=3` at `25^(@)C`. The potential of the cell would be (the value of 2.303 RT/F is 0.059 V)

A

0.177 V

B

0.087 V

C

`-0.177`V

D

0.059 V

Text Solution

Verified by Experts

The correct Answer is:
C
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise Exercise -2 (Nernst equation and EMF)|19 Videos

  • DILUTE SOLUTIONS

    AAKASH SERIES|Exercise EXERCISE - 1.2|55 Videos

  • ELEMENTS OF D - BLOCK

    AAKASH SERIES|Exercise EXERCISE - 5.2|33 Videos

Similar Questions

Explore conceptually related problems

The standard oxidation potential of Ni//Ni^(2+) electrode is 0.236 V . If this is combined with a hydrogen electrode in acid solution , at what pH of this solution will be measured e.m.f be zero at 25^@ C ? Assume that [Ni^(2+)] = 1M and P_(H_2) = 1 atm

Find the precentage degree of dissociation of 0.05 M NH_3 at 25^(@) C in a solution of pH = 11

Knowledge Check

  • The potential of hydrogen electrode at pH=10 and 25^(@)C is

    A
    0.59V
    B
    zero volts
    C
    `-0.59V`
    D
    `-0.059V`

  • The hydrogen electrode when placed in a buffer solution of CH_3COONa and CH_3COOH in the ratio x:y and y: x has oxidation electrode potential E_ and E_ volts respectively at 25^(@) C (pH_2 =1 atm) . pK_a for CH_3COOH will be :

    A
    `E_1 + E_2 `
    B
    `E_1 - E_2 `
    C
    ` (E_ 1+ E_2)/(0.0591 xx 2) `
    D
    `(E_1- E_2)/( 0.0591 xx 2)`

  • Consider the single electrode process 4H^ + 4e^- = 2H_2 catalyzed by platinum black electrode in HCl electrolyte. The potential of the electrode is -0.059V Vs. SHE. What is the concenteration of the acid in the hydrogen half cell if the H_2 pressure is 1 bar?

    A
    1M
    B
    10M
    C
    0.1M
    D
    0.01M

    • Similar Questions

    Explore conceptually related problems

    At what pH the oxidation potential of hydrogen electrode will be -0.413 V ?

    E^(0) of silver electrode is 0.8 V and solubility product of Agl is 1 xx 10^(-16) . Calculate the potential of silver electrode at 25^@C in a saturated Ago solution in water.

    The pH of 1.2 % (w/v) aqueous solution of CH_(3) COOH at 25^(@) C is (pK_(a) = 4.7)

    The electrochemical cell shown below is a concentration cell. M|M^(2+) (saturated solution of a sparingly soluble salt, MX_2 || M^(2+) (0.001 mol dm^(-3) ) |M The emf of the cell depends on the difference in concentration of M^(2+) ions at the two electrode The emf of the cell at 298 is 0.059 V The solubility product (K_(sp) , mol^(3) dm^(-9)) of MX_2 at 298 based on the information available the given concentraiton cell is (take 2.303 xx R xx 298 // F = 0.059 V )

    The electrochemical cell shown below is a concentration cell. M|M^(2+) (saturated solution of a sparingly soluble salt, MX_2 || M^(2+) (0.001 mol dm^(-3) ) |M The emf of the cell depends on the difference in concentration of M^(2+) ions at the two electrode The emf of the cell at 298 is 0.059 V The value of DeltaG (kJ " mol"^(-1)) for the given cell is ( take 1F = 96500 C " mol"^(-1) )

    Home
    Profile