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A straight line (x)/(a)+(y)/(b)=1 meets ...

A straight line `(x)/(a)+(y)/(b)=1` meets the axes in A, B.A line perpendicular to AB meets the axes in P and Q. The locus of point intersection of AQ and BP is

A

`x(x-a)+y(y-b)=0 `

B

`x(x+a)+y(y+b)=0`

C

`x(x+a)+y(y-b)=0`

D

`x(x-a)+y(y+b)=0`

Text Solution

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The correct Answer is:
A
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