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A straight line (x)/(a)+(y)/(b)=1 meets ...

A straight line `(x)/(a)+(y)/(b)=1` meets the axes in A, B.A line perpendicular to AB meets the axes in P and Q. The locus of point intersection of AQ and BP is

A

`x(x-a)+y(y-b)=0 `

B

`x(x+a)+y(y+b)=0`

C

`x(x+a)+y(y-b)=0`

D

`x(x-a)+y(y+b)=0`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The line x/a+y/b=1 cuts the coordinate axes at a and B a line perpendicular to AB meets the axes in P and Q. The equation of the locus of the point of intersection of the lines AQ and BP is

    A
    `x^(2)+y^(2)=a^(2)+b^(2)`
    B
    `x^(2)+y^(2)=a^(2)`
    C
    `x^(2)+y^(2)-ax-by=0`
    D
    `x^(2)+y^(2)+ax+by=0`

  • The line x+y=1 cuts the coordinate axes at P and Q and a line perpendicular to it meet the axes R and S. The equation to the locus of the intersection of lines PS and QR is

    A
    `x^(2)+y^(2)=1`
    B
    `x^(2)+y^(2)-2x-2y=0`
    C
    `x^(2)+y^(2)-x-y=0`
    D
    none

  • The line 3x+2y=24 meets the axes in A and B. The perpendicular bisector of AB meets the line y+1=0 at C, then area of DeltaABC=

    A
    81
    B
    91
    C
    71
    D
    61

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