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KUMAR PRAKASHAN-OBJECTIVE SECTION AS PER NEW PAPER SCHEME -Binomial Theorem (True /False Statement)
- ((n),(0))-((n),(1))+((n),(2))-((n),(3))+((n),(4))-((n),(5)).........+(...
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- The sum of the coefficients in the expansion of (a+b)^n is 4096. Then...
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- Numbers of terms in expansion (2x+3y+4z)^(7) are 8 .
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- ............ is the middle term in expansion of (2x+(1)/(2x))^(8).
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- Sum of the coefficient in expansion (x+y+z)^n is 3^n .
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- Sum of the power of a and b in expansion (a+b)^n is n .
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- Difference of (r+1) term from beginning and (r+1) term from last in ex...
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- Coefficient of x^3 in expansion (1+x)^n is 20 then n = 6 .
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- The coefficient of T(5) and T(19) in expansion (1+x)^n are equal then ...
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- ((12),(1))+((12),(3))+((12),(5))+.....+((12),(11))=2^(12).
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- ((n),(0))-((n),(1))+((n),(2))-((n),(3))+((n),(4))-((n),(5)).........+(...
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- The sum of the coefficients in the expansion of (a+b)^n is 4096. Then...
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- Numbers of terms in expansion (2x+3y+4z)^(7) are 8 .
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- ............ is the middle term in expansion of (2x+(1)/(2x))^(8).
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- Sum of the coefficient in expansion (x+y+z)^n is 3^n .
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- Sum of the power of a and b in expansion (a+b)^n is n .
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- Difference of (r+1) term from beginning and (r+1) term from last in ex...
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- Coefficient of x^3 in expansion (1+x)^n is 20 then n = 6 .
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- The coefficient of T(5) and T(19) in expansion (1+x)^n are equal then ...
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- ((12),(1))+((12),(3))+((12),(5))+.....+((12),(11))=2^(12).
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