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The angular velocity of a body is vec(om...

The angular velocity of a body is `vec(omega)=2hati+3hatj+4hatk` and a torque `vec(tau)=hati+2hatj+3hatk` acts on it. The rotational power will be

A

20W

B

15W

C

`sqrt17W`

D

`sqrt14W`

Text Solution

Verified by Experts

The correct Answer is:
A
Power `(P)= vec(tau).vec(omega)= (i+ 2hat(j) + 3hat(k)). (2hat(i) + 3hat(j) + 4hat(k))= 2 + 6+ 12= 20W`
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Knowledge Check

  • The angular velocity of a body is given by vec(omega)=3hati+2hatj+3hatk A torque vec(tau)=2hati+3hatj+4hatk acts on it. Then the rotational power will be

    A
    12 watt
    B
    24 watt
    C
    16 watt
    D
    8 watt

  • The angular velocity of a body is vecomega = 2hati + 3hatj + 4hatk "rad s"^(-1) and a torque vecr = hati + 2hatj + 3hatK m acts on it. The rotational power will be:

    A
    20 W
    B
    15 W
    C
    `sqrt(17) W`
    D
    `sqrt(14)` W

  • Find the torque of a force vecF=2hati+hatj+4hatk acting at the point vecr=7hati+3hatj+hatk :

    A
    `14hati-38hatj-16hatk`
    B
    `4hati+4hatj+6hatk`
    C
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    D
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