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The equilibrium constant for the reactio...

The equilibrium constant for the reaction `N_(2) + 3H_(2) hArr 2NH_(3) ` is 'K' . Then the equilibrium constant for the reaction `2N_(2) + 6H_(2) hArr 4NH_(3) ` will be

A

K

B

`K^2`

C

`sqrtK`

D

`2K`

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Knowledge Check

  • The equilibrium constant (K_c) for the reaction 2HCl(g) iff H_2(g) + Cl_2(g) Is 4 xx 10^(-34) at 25^@C . What is the equilibrium constant for the reaction ? 1/2 H_2(g) + 1/2Cl_2(g) iff HCl(g)

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    B
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    D
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  • For the reversible reaction N_2(g)+3H_2(g) iff 2NH_3(g) +heat The equilibrium shifts in forward direction

    A
    by increasing the concentration of `NH_3(g)`
    B
    by decreasing the pressure’
    C
    by decreasing the concentrations of `N_2(g)` and `H_2(g)`
    D
    by increasing pressure and decreasing temperature.

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    Find out the equilibrium constant for the reaction, XeO_(4)(g)+2HF(g)hArr XeO_(3)F_(2)(g)+H_(2)O(g) consider K_(1) as the equilibrium constant for the reaction, XeF_(6)(g)+H_(2)O(g)hArr XeOF_(4)(g)+2HF(g) and K_(2) as the equilibrium constant for the reaction, XeO_(4)(g)+XeF_(6)(g) hArr XeOF_(4)(g)+XeO_(3)F_(2)(g) .

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