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In the reaction 3A to 2B, rate of react...

In the reaction `3A to 2B`, rate of reaction `+('d(B)')/(dt)` is equal to

A

`-(1)/(3) (d(A))/(dt)`

B

`-(2)/(3) (d(A))/(dt)`

C

`+2(d(A))/(dt)`

D

`-(3)/(2)(d(A))/(dt)`

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Knowledge Check

  • For the reaction A + 2B to C , the reaction rate is doubled if the concentration of A is doubled The rate is increased by four times when concentrations of bothA and B are increased by four times. The order of the reactions is

    A
    3
    B
    0
    C
    1
    D
    2

  • For a reaction 1/2A rarr 2B, rate of disappearance of 'A' is related to the rate of appearance of B by the expression

    A
    `-(d[A])/dt=1/2(d[B])/dt`
    B
    `-(d[A])/dt=1/4(d[B])/dt`
    C
    `-(d[A])/dt=(d[B])/dt`
    D
    `-(d[A])/dt=4(d[B])/dt`

  • The initial rate, -(d[A])/dt at t = 0 was found to be 2.6 xx 10^2 mol L^-1s^-1 for the reaction A+ 2B to Products The initial rate, (d[B])/dt, at t approx 0 is

    A
    `0.10 mol L^-1 s^-1`
    B
    `2.6 xx 10^-2 mol L^-1 s^-1`
    C
    `5.2 xx 10^-2 mol L^-1 s^-1`
    D
    `6.5 xx 10^-3 mol L^-1 s^-1`

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    A+BrarrC , on doubling the concentration of 'A , the rate of the reaction doubles. However on doubling the concentration of B , the rate of the reaction remains unaltered. Write the rate law of the reaction.

    For the reaction A+Brarr product , (a) the rate of reaction doubles on doubling the concentration of A. (b) the rate of reaction increases by four times on doubling the concentration of B. Determine the overall order of the reaction ?

    For the reaction A+2BrarrC+D , the rate of the reaction= k[A][B]^(2) where k = rate rate constant. How can the reaction be converted to a pseudo second order reactions?

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