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Starting from rest a particle is first a...

Starting from rest a particle is first accelerated for time `t_(1)` with constant acceleration `a_(1)` and then stops in time `t_(2)` with constant retardation `a_(2)`. Let `v_(1)` be the average velocity in this case and `s_(1)` the total displacement. In the second case, it is accelerated for the same time `t_(1)` with constant acceleration `2a_(1)` and comes to rest with constant retardation `a_(2)` in time `t_(3)` . If `v_(2)` is the average velocity in this case and `s_(2)` the total displacement . Then

A

`v_(2)=2v_(1)`

B

`2v_(1) lt v_(2) lt 4v_(1)`

C

`s_(2) = 2s_(1)`

D

`2s_(1) lt s_(2) lt 4s_(1)`

Text Solution

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The correct Answer is:
A, D
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