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Calculate the wavelength and energy of radiation emitted for the electronic transition from infinity `(infty)` to stationary state of one of hydrogen atom.

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Knowledge Check

  • The electronic transition from n=2 to n=1 will produce shortest wavelength in:

    A
    H atom
    B
    D atom
    C
    `He^+ ion`
    D
    `Li^(2+)`

  • While electron in hydrogen atom revolves in a stationary orbit it

    A
    radiates light but its velocity is unchanged
    B
    does not radiate light but its velocity remains unchanged
    C
    does not radiate though its velocity changes
    D
    radiates light with the change of energy

  • Energy of the lowest level of H-atom is-13.6 eV. The energy of the emitted photons in transition from fourth to second energy state is of:

    A
    2.55eV
    B
    3.2eV
    C
    4.5 eV
    D
    5.4 eV

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