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In acidic medium, the reaction, MnO4^(1-...

In acidic medium, the reaction, `MnO_4^(1-) rarr Mn^(2+)` involves :

A

Oxidation by 3 electrons

B

Reduction by 3 electrons

C

Oxidation by 5 electrons

D

Reduction by 5 electrons

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • In the reaction HgCl_2 + 4KI rarr M + 2KCl , A is :

    A
    `HgI_2`
    B
    `K_2HgI_3`
    C
    `K_2HgI_4`
    D
    `KHgI_3`

  • In the reaction HgCl_2 + 4KI rarr M + 2KCl , A is :

    A
    `HgI_2`
    B
    `K_2HgI_3`
    C
    `K_2HgI_4`
    D
    `KHgI_3`

  • In the reaction SnCl_(2) + 2HgCI_(2)rarr A + SnCl_(4) ,

    A
    `HgCl_(2)`
    B
    `Hg`
    C
    `HgCl`
    D
    `HgCl_(3)`

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    Balance the equation MnO_4^- +H^+ +Fe^2 rarr Mn^2 + H_2O + Fe^3^+

    When KMnO_4 is reduced with oxalic acid in acid medium, the oxidation number of Mn changes from :

    The charge required for the reduction of 1 mol MnO_4^(-) to MnO_2 is

    Fill up the gap in the following equation, MnO_4^-+8H^+ - rarrMn^(2+) +4H_2O

    In acidic medium, permanganate is reduced to Mn^(2+) by excess of reducing agent as MnO_4-+8H^+5e Mn_(2+) +4H_2O .Therefore, the equivalent mass of KMnO_4 is obtained on dividing its nolecular mass by :

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