Explain the following :
`Pb^(4+)` acts as an oxidizing agent but `Sn^(2+)` acts as a reducing agent .

Explanation

`Pb^(4+)` by gaining 2 electrons changes into `Pb^(2+)` which is more stable due to inert pair effect . `Sn^(2+)` is less stable than `Sn^(4+)` by losing electrons. Therefore , `Pb^(4+)` acts as an oxidizing agent while `Sn^(2+)` acts as a reducing agent.
`Sn^(2+) to Sn^(+4) + 2e^(-)`
`Pb^(4+) + 2e^(-) to Pb^(2+)`