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z=i+sqrt(3)=r(cos theta+sin theta)...

`z=i+sqrt(3)=r(cos theta+sin theta)`

Text Solution

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The correct Answer is:
`(pi)/(6)`
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Knowledge Check

  • Integration using rigonometric identities : int(sin theta)/(cos3 theta)+(sin 3 theta)/(cos9 theta)+( sin9 theta)/(cos 27theta)d theta=...+c

    A
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    D
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