A ray of light travelling along the line...

A ray of light travelling along the line x+y = 1 line incident on the x-axis and after rrefraction it enters the other side of the x-axis by turing `pi//6` away from the x-axis. The equation of the line along which the refracted ray travels is

`x+(2-sqrt3)y=1`

`(2-sqrt3)x+y=1`

`y+(2+sqrt3)x=2+sqrt3`

`y+(2-sqrt3)x=2-sqrt3`

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The correct Answer is:

A, C, D

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A beam of light is sent along the line x-y=1, which after refracting from the x-axis enters the oppositi side by turining through 30^@ towards the normal at the point of incidence on the x-axis. Then the equation of the refracrted ray is

`(2-sqrt3)x-y=2+sqrt3`

`(2+sqrt3)x-y=2+sqrt3`

`(2-sqrt3)x-y=2+sqrt3`

`y=(2-sqrt3)(x-1)`

`|y|=x+2`

`|y|+2=x`

`y=|x-2|`

`y=|x-1|`

`a=64/115,b=112/15`

`a=14/15,b=112/15`

`a=64/115,b=(-8)/115`

`a=64/15,b=14/15`