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The extremites of the base of an isoscel...

The extremites of the base of an isosceles triangle are (2,0) and (0,2). If the equation of one of the equal side is x=2, then the equaiton of other unequal side is

A

`x+y=2`

B

`x-y+2=0`

C

`y=2x-1`

D

`2x+y=2`

Text Solution

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The correct Answer is:
C
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AAKASH SERIES-STRAIGHT LINES-PRACTICE SHEET(EXERCISE-I Problems on slopes, Equation of Lines and Interceptes of a line , Areas) (LEVEL -I Straight Objective Type Question)
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