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The extremites of the base of an isoscel...

The extremites of the base of an isosceles triangle are (2,0) and (0,2). If the equation of one of the equal side is x=2, then the equaiton of other unequal side is

A

`x+y=2`

B

`x-y+2=0`

C

`y=2x-1`

D

`2x+y=2`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • The ends of the base of an isoceles triangle are at (2a, 0) and (0, a). The equation of one side is x=2a . The equation of the other side is

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