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A (1,3) and C (-2/5,-2/5) are the vertic...

A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the internal angle bisector of `angleABC is x+y =2`
Equation of BC is

A

7x+3y+4=0

B

3x+7y+4

C

13x+7y+8=0

D

x+9y+4=0

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The correct Answer is:
A
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Knowledge Check

  • A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the angle bisector of angleABC is x+y =2 Equation of side AB is

    A
    `13x-7y+8=0`
    B
    `13x+7y-34=0`
    C
    `3x+7y-24=0`
    D
    `3x+7y+24=0`

  • A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the internal angular bisector of angleABC is x+y -2=0 Coordinates of vertex B

    A
    `(3/10,17/10)`
    B
    `(17/10,3/10)`
    C
    `(-5/2,9/2)`
    D
    (1,1)

  • The vertices of a trianvle are A(-1,-7),B(5,1) and C(1,4). The equation of the bisector of /_ABC is

    A
    `x-7y+2=0`
    B
    `x+y-6=0`
    C
    `x+2y-7=0`
    D
    `116x-39y=157`

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