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If A=[(a^(2),ab,ac),(ab,b^(2),bc),(ac,bc...

If `A=[(a^(2),ab,ac),(ab,b^(2),bc),(ac,bc,c^(2))]` and `a^(2)+b^(2)+c^(2)=1`, then `A^(2)=`

A

2A

B

A

C

3A

D

`1/2`A

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • |(-a^(2),ab,ac),(ab,-b^(2),bc),(ac,bc,-c^(2))|=

    A
    `a^(2)b^(2)c^(2)`
    B
    `2a^(2)b^(2)c^(2)`
    C
    `3a^(2)b^(2)c^(2)`
    D
    `4a^(2)b^(2)c^(2)`
  • |(a^(2)+x,ab,ac),(ab,b^(2)+x,bc),(ac,bc,c^(2)+x)|

    A
    `a^(2)+b^(2)+c^(2)+x`
    B
    `(a^(2)+b^(2)+c^(2)+x)x^(3)`
    C
    `(a^(2)+b^(2)+c^(2)+x)x^(3)`
    D
    none
  • |(a^(2)+1,ab,ac),(ab,b^(2)+1,bc),(ac,bc,c^(2)+1)|=

    A
    `1+a+b+c`
    B
    `1+a^(2)+b^(2)+c^(2)`
    C
    `abc+ab+bc+ca`
    D
    none
  • Similar Questions

    Explore conceptually related problems

    I: |(-a^(2),ab,ac),(ab,-b^(2),bc),(ac,bc,-c^(2))|=2a^(2)b^(2)c^(2) II: |(0,ab^(2),ac^(2)),(a^(2)b,0,bc^(2)),(a^(2)c,b^(2)c,0)|=2a^(3)b^(3)c^(3)

    |(b^(3)+c^(2),ab,ac),(ab,c^(2)+a^(2),bc),(ca,bc,a^(3)+b^(2))|=

    |(1//a,a^(2),bc),(1//b,b^(2),ca),(1//c,c^(2),ab)|=

    |(a,b,c),(a^(2),b^(2),c^(2)),(bc,ca,ab)|=

    |((a+b)^(2),ca,bc),(ca,(b+c)^(2),ab),(bc,ab,(c+a)^(2))|=