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Let gas (A) present in air is dissolved ...

Let gas (A) present in air is dissolved in 20 moles of water at 298K and 20 atm pressure. The mole fraction of gas (A) in air is 0.2 and the Henry's law constant for solubility of gas (A) in water at 298K is `1×10^5`atm.The number of mole of gas (A) dissolved in water will be

A

`8×10^(-5)`

B

`4×10^(-4)`

C

`8×10^(-4)`

D

`6×10^(-5)`

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  • When a gas is bubbled through water at 298 K, a very dilute solution of gas is obtained . Henry's law constant for the gas is 100 kbar. If gas exerts a pressure of 1 bar, the number of moles of gas dissolved in 1 litre of water is

    A
    0.555
    B
    `55.55xx10^(-5)`
    C
    `55.55xx10^(-3)`
    D
    `5.55xx10^(-5)`

  • N_(2) gas is bubbled through water at 293 K and the partial pressure of N_(2) is 0.987 bar .If the henry's law constant for N_(2) at 293 K is 76.84 kbar, the number of millimoles of N_(2) gas that will dissolve in 1 L of water at 293 K is

    A
    `1.29`
    B
    `0.716`
    C
    `2.29`
    D
    `7.16`

  • Volume of 0.5 mole of a gas at 1 atm. Pressure and 273 K is

    A
    22.4 litres
    B
    11.2 litres
    C
    44.8 litres
    D
    5.6 litres

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