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In the Carius method of estimation of ha...

In the Carius method of estimation of halogen. 0.25 g of an organic compound gave 0.188 g of AgBr. The percentage of bromine in the compound is
(Molar mass of AgBr = 188 g `mol^-1` )

A

0.25

B

0.2

C

0.32

D

0.38

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Knowledge Check

  • 0.4 g of Organic Compound gave 0.188 g of AgBr. The percentage of Br in the compound is

    A
    39.8
    B
    `46.0`
    C
    `20.0`
    D
    `40.0`

  • In Carium method of estimation of halgoen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?

    A
    0.6808
    B
    0.3504
    C
    `42.1%`
    D
    0.5

  • In Carcuc method for the estimation of halogens. 250 mg of organic compound gave 141 mg of AgBr . The percentage of bromine in the compound is :

    A
    48
    B
    60
    C
    24
    D
    36

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    In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr . The percentage of bromine in the compound is: (at mass Ag=108 , Br =80 )

    In Carius method of estimation of halogen, 250mg of an organic compound gave 141mg of AgBr. The percentage of bromine in the compound is (Ag= 108, Br= 80)

    In carius method of estimation of halogens, 250 mg of organic compound gave 141 mg of AgBr. Th percentage of bromine in the compound is (at mass Ag = 108 , Br = 80)

    In Carius method of estimation of halogens 250 mg of an organic compound gave 141 mg of AgBr . The percentage of bromine in the compound is (atomic mass Ag = 108, Br = 80 )

    In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentageof bromine in the compound is : (Atomic mass Ag = 108, Br = 80)

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