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Based on bond order compare the relative...

Based on bond order compare the relative stabillity of `O_2` and `O_2^(2-)`

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Paramagnetism is related to number of unpaired electrons. Compare the stabilities of O_2 and O_2^(-) using bond order.

Compare relative stability of following carbocation:

Knowledge Check

  • Compare relative stability of following carbocation:

    A
    `igtiigtiii`
    B
    `iiigtigtii`
    C
    `igtiiigtii`
    D
    `iiigtiigti`

  • The bond order of O_2 molecule is

    A
    1
    B
    2
    C
    2.5
    D
    3

  • Arrange the following species in the correct order of their stability C _(2), Li _(2),O_(2) ^(+) He _(2) ^(+)

    A
    `Li _(2) lt He _(2) ^(+) lt O _(2) ^(+)`
    B
    `C _(2) lt O _(2) ^(+) lt Li _(2) He _(2) ^(+)`
    C
    `He _(2) ^(+) lt Li _(2) lt C _(2)lt O _(2) ^(+)`
    D
    `O _(2) ^(+) lt C_(2) lt Li _(2) lt He _(2) ^(+)`

    • Similar Questions

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    Based on M.O elecrtonic configuration, compare the magnetic property of O_2 and O_2^2-

    What is meant by the term bond order? Calculate the bond order of: N_2 , O_2 , O_2^+ and O_2^- .

    Compare the structure of H_2O and H_2O_2 .

    Define bond order according to the M.O.theory.

    In the following question, an Assertion (A) is followed by a corresponding Reason (R). Use the following keys to choose the appropriate answer. Assertion : F_2 and O_2^(2-) have bond order 1 while N_2 , CO and NO^(+) have bond order 3. Reason : Higher the bond order, higher is the stability of the molecule.

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