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In DeltaABC and DeltaPQR, in a one to on...

In `DeltaABC and DeltaPQR`, in a one to one correspondence.
`(AB)/(QR) = (BC)/(PR) = (CA)/(PQ)`, then

A

(a) `DeltaPQR ~ DeltaABC`

B

(b) `DeltaPQR ~ DeltaCAB`

C

(c) `DeltaCBA ~ DeltaPQR`

D

(d) `DeltaBCA ~ DeltaPQR`

Text Solution

Verified by Experts

The correct Answer is:
B
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