Home
Class 12
MATHS
The value of c in (0,2) satisfying the M...

The value of c in (0,2) satisfying the Mean Value theorem
for the function `f(x)=x(x-1)^(2), x epsilon[0,2]` is equal to

A

(a) `3/4`

B

(b) `4/3`

C

(c) `1/3`

D

(d) `2/3`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

Varify Lagrange's mean value theorem for the function f(x)=x+(1)/(x), x in [1, 3]

Verify Rolle's theorem for the function f(x)= x^(2)-4x + 10 on[0, 4]

Verify Lagrange's mean value theorem for the following functions. f(x)= 2x-x^(2), x in [0,1]

The value of c in mean value theorem for the function f(x)= x^2 in [2,4] is A)3 B)2 C)4 D)7/2

The value of c in Lagrange's mean value theorem for the function f(x)=log_ex in the interval [1,3] is

Verify Lagrange's mean value theorem for the function f(x)= x+ (1)/(x) on the interval [1, 3]

Verify Rolle's theorem for the function: f(x) = x^2 -4x +10 on (0,4)

Verify Lagrange's mean value theorem for the following functions: f(x) = 2x - x^2 , x in [0,1]

Verify Lagrange's mean value theorem for the following functions. f(x)= (x-1) (x-2) (x-3) on [0,4]

Verify Lagrange's mean value theorem for the following functions: f(x) = (x-1)(x-2)(x-3) on [0,4]

Home
Profile