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If the work function of a metal is 'phi'...

If the work function of a metal is `'phi'` and the frequency of the incident light is `'v'`, there is no emission of photoelectron if

A

`vltphi/h`

B

`v=phi/h`

C

`vgtphi/h`

D

`vgephi/h`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The photoelectric threshold frequency of a metal is v_0. When ligth of frequency 3v_0 is incident on the metal, the maximum kinetic energy of emitted photoelectrons will be

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  • The work function of metal is 1 eV. Ligth of wavelength 3000 Å is incident on this metal surface. The velocity of emitted photoelectrons will be

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    D
    `1xx10^6 m//s`

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