In three moles of ethane `(C_(2)H_(6))` calculate the following :
(i) Number of moles of carbon atoms.
(ii) Number of moles of hydrogen atoms.
(iii) Number of molecules of ethane.

Explanation

(i) 2 mol carbon mplecule present in 1 mole ethane. So, 6 mol carbon molecule present in three mol ethane.
(ii) 6 mol Hydrogen molecule are in 1 mol ethane `(C_(2)H_(6))`. Therefore in three mole ethane `3xx6 = 18` molecules of hydrogen present.
(iii) 1 mol ethane `= 6.022xx10^(23)` ethane molecule
`:. 3` mol ethene `= (?)`
`= 3 xx 6.022xx10^(23)`
`= 18.066xx10^(23)` ethane molecule