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The ionisation energy of hydrogen atom (...

The ionisation energy of hydrogen atom (in the ground state) is x kJ. The energy required for an electron to jump from `2^(nd)` orbit to the `3^(rd)` orbit will be

A

x/6

B

5x

C

7.2x

D

5x/36

Text Solution

Verified by Experts

The correct Answer is:
D
`(I.E)_H=E_oo- E_1=-E_1=x`
Put `E_1=-K/n^2=-K/1^2=-K, therefore K=x`
`DeltaE=E_3-E_2=-K/3^2 - (-K/2^2)=K5/36=5/36x`
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